Answer:
[tex]4 \frac{1}{9}x[/tex] + [tex]12\frac{1}{3}[/tex] = 0
Step-by-step explanation:
Based on 2x - 9y - 12 = 0
-9y = 12 - 2x
9y = -12 + 2x
y = [tex]-1\frac{1}{3} + \frac{2}{9} x[/tex]
Therefore...
5x - 4y + 7 = 0
5x - 4([tex]-1\frac{1}{3} + \frac{2}{9} x[/tex]) + 7 = 0
5x + [tex]5\frac{1}{3}[/tex] - [tex]\frac{8}{9} x[/tex] + 7 = 0
[tex]4 \frac{1}{9}x[/tex] + [tex]12\frac{1}{3}[/tex] = 0
