Answer:
[tex]p =\frac{1}{6}[/tex]
Step-by-step explanation:
Given
[tex]Polygons =\{Quadrilateral, Pentagon, Hexagon, Octagon, Nonagon, Decagon\}[/tex]
Required
Probability of assigning a nonagon
From the given set of polygons, there are 6 polygons in the set and 1 one of them is a nonagon
This means that:
[tex]n = 6[/tex] --- Total
[tex]Nonagons = 1[/tex]
So, the probability, p is:
[tex]p =\frac{Nonagons}{n}[/tex]
[tex]p =\frac{1}{6}[/tex]
