Let's solve this problem step-by-step:
Let's set:
[tex]-2x + 2y = 6 -- equation 1\\7x+4y=23 -- equation 2[/tex]
(equation1) * 2
[tex]-4x+4y=12--equation3[/tex]
(equation 2) - (equation 3)
[tex]11x = 35\\x= \frac{11}{11}--equation4\\x=1[/tex]
Plug (equation4)'s value of 'x' into (equation1)
[tex]-2(1} )+2y=6\\-2+2y =6 \\2y = 6+2 =8 \\y =4[/tex]
Thus x= 1 and y = 4
Let's check:
[tex]-2(1 )+2(4)=6\\2 +4 =6\\6=6\\ \\7(1)+4(4) )=23\\7+16=23\\ 23 =23\\[/tex]
Answer: x = 1 and y= 4
Hope that helps!
