Answer: x = 0
Step-by-step explanation:
Subtract 6x^3+29x^2+47x+28 from both sides:
(2^2 + x + 4) (x - 7) - 6x^3+29x^2+47x+28
(6x^3+29x^2+47x+28)-6x^3+29x^2+47x+28
= -4x^3 - 14x^2 - 36x = 0
Now factor the left side:
-4x^3 - 14x^2 - 36x = 0
(-2x) (2x^2 + 7x + 18) = 0
Now set the factors equal to 0
-2x = 0 or 2x^2 + 7x + 18 = 0
x = 0
