Answer:
10 and -5
Step-by-step explanation:
x + y = 5
xy = -50
y = 5 - x
x(5-x) = -50
5x - x^2 = -50
x^2 - 5x - 50 = 0
from there on we can solve the classic way
[tex]\Delta = (-5)^2 - 4\cdot1\cdot(-50) = 25 + 200 = 225\\\sqrt{\Delta} = 15\\x_1 = \frac{5 - 15}{2} = -5\\x_2 = \frac{5+15}{2} = 10\\y_1 = 5 - x_1 = 10\\y_2 = 5 - x_2 = -5[/tex]
Everything checks out.
