Answer:
3.11 is the pH of the solution
Explanation:
The ionised form of the acetic acid is the acetate ion. To solve this problem we need to solve H-H equation:
pH = pKa + log [A⁻] / [HA]
Where pH is the pH of the buffer
pKa = -log Ka = 4.74
[A⁻] = Concentration of acetate ion = 0.002M * 2.3% = 4.6x10⁻⁵M
[HA] = Concentration of acetic acid = 0.002M *(100-2.3)% = 0.001954M
Replacing:
pH = 4.74 + log [4.6x10⁻⁵M] / [0.001954M]
pH = 3.11 is the pH of the solution
