Answer:
[tex]2.03\times 10^5\ Pa[/tex]
Explanation:
We need to find the extra pressure when you are 10 meters under water. The net pressure on us is given by :
[tex]P=P_o+\rho gh\\\\P=1.05\times 10^5+1000\times 9.8\times 10\\\\P=2.03\times 10^5\ Pa[/tex]
So, [tex]2.03\times 10^5\ Pa[/tex] is exerted on us at 10 m under water.
