Answer:
[tex]2Na + Ca^{2+} \rightarrow Ca + 2Na^+[/tex]
Explanation:
Hello!
In this case, since this a reaction in which the oxidation state of the metals is changing, we need to apply a redox method for which:
[tex]Na\rightarrow Na^++e^-\\\\Ca^{2+}\rightarrow Ca+2e^-\\\\\\2Na\rightarrow 2Na^++2e^-\\\\Ca^{2+}\rightarrow Ca+2e^-[/tex]
Thus, the result is:
[tex]2Na + Ca^{2+} \rightarrow Ca + 2Na^+[/tex]
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