Answer:
the net work done on the cart is 160 J.
Explanation:
Given;
mass of the cart, m = 5.0 kg
initial velocity of the cart, u = 6 m/s
final velocity of the cart, v = 10 m/s
The net work done on the cart is equal to change in average kinetic energy of the cart;
[tex]W = K.E = \frac{1}{2} m(v^2-u^2)\\\\W = \frac{1}{2} \times 5(10^2-6^2)\\\\W = 160 \ J[/tex]
Therefore, the net work done on the cart is 160 J.
