Answer:
[tex]\Large \boxed{\sf 2\sqrt{41} }[/tex]
Step-by-step explanation:
Use Pythagorean theorem formula
[tex]a^2+b^2=c^2[/tex]
a and b are legs and c is hypotenuse of the right triangle.
Solve for c
[tex]\displaystyle c=\sqrt{a^2+b^2}[/tex]
Substitute a = 8 and b = 10
[tex]\displaystyle c=\sqrt{8^2+10^2}[/tex]
[tex]\displaystyle c=2\sqrt{41}[/tex]
