Answer:
The equation of a line passing through points [tex](x_1,y_1)[/tex]and [tex](y_1,y_2)[/tex] is given by:
[tex]y-y_1 = \frac{(y_2-y_1)}{x_2-x_1}(x-x_1)[/tex]
According to question, the passing points of the line are (1,1) and (3,-3). So, its equation is given by:
[tex]y-1 = \frac{-3-1}{3-1} (x-1) \\or, y-1 = \frac{-4}{2}(x-1)\\or, 2y-2 = -4x+4\\or, 4x + 2y = 2+4\\or, 4x+2y = 6\\or, 2x+y = 3 is the required equation.[/tex]
