Answer:
[tex]x^2+(y+1)^2=2[/tex]
Step-by-step explanation:
We use the formula for a circle with center at (0, -1), that goes through the (x, y) point (-1, -2):
[tex](x-0)^2 + (y-(-1))^2 = R^2\\Using \,\,\,point\,\,\,(-1, -2)\\(-1-0)^2+ (-2+1)^2 = 1 + 1 = 2 = R^2[/tex]
Therefore, the equation of this circle can be written as:
[tex]x^2+(y+1)^2=2[/tex]
