Answer:
The slope of line perpendicular to line q is 8/3.
Step-by-step explanation:
Given that:
Slope of a line q is -3/8
Slope is the steepness of any line.
Let,
x be the slope of line perpendicular to line q.
The product of slopes of two perpendicular lines is equal to -1.
[tex]\frac{-3}{8}x = -1[/tex]
Multiplying both sides -8/3
[tex]\frac{-8}{3}*\frac{-3}{8}x=-1*\frac{-8}{3}[/tex]
x = 8/3
Hence,
The slope of line perpendicular to line q is 8/3.
