9514 1404 393
Answer:
{-1.47, 1.14}
Step-by-step explanation:
The solution to ...
ax^2 +bx +c = 0 is ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Filling in the values a=3, b=1, c=-5, the solutions are ...
[tex]x=\dfrac{-1\pm\sqrt{1^2-4(3)(-5)}}{2(3)}=\dfrac{-1\pm\sqrt{61}}{6}\\\\\boxed{x\approx\{-1.47,1.14\}}[/tex]
