Answer:
=4t−3
Step-by-step explanation:
1 /5 (20t−15)
1 /5 (20t+−15)
1 /5 )(20t)+( 1/ 5 )(−15)
[tex]\huge\boxed{4t-3}[/tex]
[tex]\dfrac{1}{5}(20t-15)\qquad|\text{use the distributive property}\ a(b+c)\\\\=\left(\dfrac{1}{5}\right)(20t)-\left(\dfrac{1}{5}\right)(15)=4t-3[/tex]
