saifahsc saifahsc
  • 03-01-2021
  • Mathematics
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rebeccarayshma
rebeccarayshma rebeccarayshma
  • 03-01-2021

Answer:

[tex] \frac{3 {x}^{2} }{2y {}^{4} } [/tex]

Step-by-step explanation:

[tex] \frac{21x {}^{6}y {}^{5} }{14 {x}^{2} y {}^{9} } [/tex]

i) divide the numbers

[tex]( \frac{21}{14})( \frac{x {}^{6} y {}^{5} }{ {x}^{2}y {}^{9} }) [/tex]

[tex]( \frac{3}{2} )( \frac{x {}^{6} y {}^{5} }{ {x}^{2}y {}^{9} }) [/tex]

ii) simplify the like terms with the same base by substracting their exponents

[tex]( \frac{3}{2} )(x {}^{6 - 2} y {}^{5 - 9} )[/tex]

[tex]( \frac{3}{2} )(x {}^{4} y {}^{ - 4} )[/tex]

[tex] \frac{3x {}^{2} }{2y {}^{4} } [/tex]

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