Answer:
dhdhrjfidgegehfr fhfn fhc fn dncc c. f byn
Step-by-step explanation:
h(t) = -16t² + 64t + 32
When h(t) = 80, -16t² + 64t + 32 = 80.
=> 16t² - 64t + 48 = 0
=> t² - 4t + 3 = 0
=> (t - 1)(t - 3) = 0
=> t = 1 or t = 3.
Hence the difference between the times is 2 seconds. (B)
