Answer:
The inequality is equivalent to x(x+2)(x−3)>0 , with the additional conditions that x≠0 and x≠3 .
Since x(x+2)(x−3) only changes signs when crossing −2 , 0 and 3 , from the fact that the evaluating the polynomial at 4 yields 24 , we see that the polynomial is
positive over (3,∞)
negative over (0,3)
positive over (−2,0)
negative over (−∞,−2)
Thus the solution set for your inequality is (−2,0)∪(3,∞) .
Step-by-step explanation:
hi Rakesh here is your answer :)
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