Answer:
[tex]18x^{5}y^{4}z[/tex]
Step-by-step explanation:
we have
[tex](6xy^{3}z)(3x^{2} yx^{2})[/tex]
Group terms that contain the same variable
[tex](6*3)(x*x^{2}*x^{2})(y^{3}*y)(z)[/tex]
Using
[tex]x^a\cdot x^b=x^{a+b}[/tex]
[tex](18)(x^{1+2+2})(y^{3+1})(z)[/tex]
[tex](18)(x^{5})(y^{4})(z)[/tex]
[tex]18x^{5}y^{4}z[/tex]
