Answer:
2[tex]\sqrt{y} * \sqrt{3} x^2[/tex]
Explanation:
1) what is the square root of 4? 2!
2x[tex]\sqrt{y} *sqrt{3x^2}[/tex]
2) [tex]\sqrt{3x^{2} }[/tex]= [tex]\sqrt{3x}[/tex] = 2[tex]\sqrt{3} xx \sqrt{y}[/tex]
3) Apply the exponent rule : xx=x^1+1
= 2[tex]\sqrt{y}[/tex] [tex]\sqrt{3} x^2[/tex]
4) Add the numbers: 1+1=2
= 2[tex]\sqrt{y} \sqrt{3} x^2[/tex]
