Answer:
The area of the given trapezoid is 22[tex]unit^2[/tex]
Step-by-step explanation:
We need to find the area of the trapezoid JKLM formed by the given coordinates which are
J(-4,3) K(-2,7) L(2,7) M (3,3)
Area of trapezoid is given by = [tex]\frac{1}{2}* (sum of parallel side( a+b ))* height[/tex]
parallel points are k(-2,7) and L(2,7) , J (-4,3) and (3,3)
a= 4 ,b=7
height = 4
upon substituting these values in the equation
A=[tex]\frac{1}{2}*(11)*4[/tex] = 22[tex]unit^2[/tex]
