Answer:
2ns
Explanation:
Given that after 2 ns, a first instruction Instr1 would be accomplished with stage 1. This implies that Instr2 could commence in stage 1. It should be noted that 1ns is too short: that is, Instr1 would only be halfway through stage 1, thereby Instr2 began to use stage 1, leading to a problem.
Also, the general equation is 12 ns / 6 stages which equals 2ns between instruction.
