Answer:
Energy emitted by photon = 45.06 × 10−32 J
Explanation:
Energy of photon is given by E = hf
where
h is the Planck's constant whose value is 6.626×10−34J⋅s
f is the frequency of photon
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given that
f = 6.8 x 104 Hz
1 HZ = 1 s^-1
E = 6.626×10−34J⋅s * 6.8 x 10^4 Hz
E = 45.06 × 10−32 J
Thus,
Energy emitted by photon is 45.06 × 10−32 J
