Answer:
x^2 + y^2 - 6x + 3y -13 =0
Step-by-step explanation:
we have formula when endpoints of diameter of circle are given.
(x-x1)(x-x2)+(y-y1)(y-y2)=0
put value of x1,x2 and y1 and y2.
=(x-5)(x-1) + {y-(-6)}(y-3)=0
=(x^2 -x - 5x +5) + ( y+6)(y-3)=0
=x^2 - 6x +5 + y^2 - 3y +6y - 18=0
=x^2 + y^2 - 6x + 3y -13=0
required equation..
