Respuesta :

lucycruz626
I would go with D. 2x^2+3/2x-5

Answer: D) [tex]2x^{2} +\frac{3x}{2} -5[/tex]

Step-by-step explanation:

[tex]f(x)=\frac{x}{2} -2 \\g(x)= 2x^{2} +x-3\\\\\(f+g)(x)\\\[/tex]

[tex]\frac{x}{2} -2 +2x^{2} +x-3\\2x^{2} +\frac{x}{2} +x-5\\\\(f+g)(x)= 2x^{2} +\frac{3x}{2} -5[/tex]

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