Answer:
Mass of KBr present = 2.23 g
Explanation:
Number of moles of KBr present in 75.0 ml of 0.250 M solution of KBr is first determined
From the formula: molarity = number of moles/ volume (L);
Number of moles = molarity * volume (L)
Volume of solution in Litres = 75/1000 = 0.075
Number of mole = 0.250 * 0075 = 0.01875 moles
Mass = number of moles * molar mass
Molar mass of KBr = 119 g/mol
Mass = 0.01875 moles * 119 g/mol = 2.23 g
