Answer:
[tex]f^{-1}[/tex](x) = (x - 2)² - 6
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = [tex]\sqrt{x+6}[/tex] + 2 ( subtract 2 from both sides )
y - 2 = [tex]\sqrt{x+6}[/tex] ( square both sides )
(y - 2)² = x + 6 ( subtract 6 from both sides )
(y - 2)² - 6 = x
Change y back into terms of x with x = [tex]f^{-1}[/tex](x) , thus
[tex]f^{-1}[/tex](x) = (x - 2)² - 6
