Answer:
a = 0, b = 6, c = 4
Step-by-step explanation:
Given
f(x) = - x² + x + 6 , then
f(- 2) = - (- 2)² + (- 2) + 6 = - 4 - 2 + 6 = 0 ← a
f(0) = 0 + 0 + 6 = 6 ← b
f(2) = - (2)² + 2 + 6 = - 4 + 2 + 6 = 4 ← c
a = 0
b = 6
c = 4
f(x) = -x² + x + 6
a = -(-2)² + (-2) + 6 = 0
b = -(0)² + (0) + 6 = 6
c = -(2)² + (2) + 6 = 4
