Answer:
[tex]x\geq -4[/tex]
Step-by-step explanation:
So we have the inequality:
[tex]3(x+6)-2(x+2)\geq 10[/tex]
First, distribute:
[tex](3x+18)+(-2x-4)\geq 10[/tex]
Combine like terms:
[tex](3x-2x)+(18-4)\geq 10[/tex]
Add:
[tex]x+14\geq 10[/tex]
Subtract 22 from both sides:
[tex]x\geq -4[/tex]
And we're done!
