batmansbae17 batmansbae17
  • 02-09-2016
  • Mathematics
contestada

Find the sum. (2a2 + ab + 2b) + (4a2 − 3ab + 9)

Respuesta :

dalendrk
dalendrk dalendrk
  • 02-09-2016
[tex](2a^2+ab+2b)+(4a^2-3ab+9)\\\\=2a^2+ab+2b+4a^2-3ab+9\\\\=(2a^2+4a^2)+(ab-3ab)+2b+9\\\\=\boxed{6a^2-2ab+2b+9}[/tex]
Answer Link
SerenaBochenek SerenaBochenek
  • 20-02-2019

Answer:

The sum is  [tex]6a^2-2ab+2b+9[/tex]

Step-by-step explanation:

Given two expression

[tex](2a^2 + ab + 2b)[/tex] and [tex](4a^2 − 3ab + 9)[/tex]

We have to find the sum of above two expression.

[tex](2a^2 + ab + 2b)+(4a^2 - 3ab + 9)[/tex]

Combining like terms we get

[tex](2a^2+4a^2)+(ab-3ab)+2b+9[/tex]

= [tex]6a^2-2ab+2b+9[/tex]

The sum is  [tex]6a^2-2ab+2b+9[/tex]

Answer Link

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