Answer:
Step-by-step
Let the given number be n>2.
For n even, n2+((n/2)2–1)2=((n/2)2+1)2.
For n odd, n2+((n2–1)/2)2=((n2+1)/2)2
use the forumla to find u r answer
standard form of a pythagorean triplet is 2m, m²+1, m²-1
let us take 2m as 36. so
2m=36, m=36/2
therefore m=18
m²+1 =18²+1 = 324+1 =325
m²-1 =18²-1 = 324-1 =323
therefore 36,325,323 form a pythagorean triplet.
For checking, 36²+323² should be equal to 325²
Tell me if this was helpful....
