Answer:
y=2(x square)-2x-3
Step-by-step explanation:
Let dy with y varibles in a hand
And dx with x variables on the other hand
dy=(4x-2)dx
Then by integration
y=2(square x)-2x+constant
Then substitute by x=-1 and y=1 to find the value of the constant
1=2(1)-2(-1)+ constant
Then constant=-3
Then the equation is
y=2(x square)-2x-3
