Answer:
The function g(x) is odd.
Step-by-step explanation:
Even and odd functions:
If for every value of x, f(x) = f(-x), the function is even.
If for every value of x, f(x) = -f(x), the function is odd.
If those statements are false, the function is neither even nor odd.
In this question:
[tex]g(x) = x^{3}[/tex]
[tex]g(-x) = (-x)^{3} = -x^{3} = -g(x)[/tex]
Since g(x) = -g(-x), the function g(x) is odd.
