Answer:
The 96th term of the given AP is (-1048)
Step-by-step explanation:
We have, the given AP is :
-3, -14, -25....
First term is -3
Common difference is -14 - (-3)= -11
Let [tex]a_{96}[/tex] is the 96th term of the AP.
The nth term of the AP is given by :
[tex]a_n=a+(n-1)d[/tex]
Put all the values, such that,
[tex]a_{96}=(-3)+(96-1)\times (-11)\\\\a_{96}=-1048[/tex]
So, the 96th term of the given AP is (-1048).
