Respuesta :

caylus
Hello,

Something is still missing


y=-a²(x+1)²+0 with a point of the parabola we can determine a²

a² is a real positive.
dalendrk
The vertex form: y = a(x - h)² + k
(h; k) the coordinates of vertex

(-1; 0) ⇒ h = -1 and k = 0

therefore y = a(x + 1)²

A parabola opens down, therefore a < 0.

Answer: y =a(x + 1)² where a < 0.