Answer:
1600 calories
Explanation:
Data obtained from the question include:
M (mass of water) = 20g
T1 (initial temperature) = 383°C
T2 (final temperature) = 303°C
ΔT (change in temperature) = T1 - T2 = 383 - 303 = 80°C
C (specific heat capacity of water) = 1 calorie/g°C
Q (heat) =?
Using the the equation Q = MCΔT, the heat in calories absorbed by the water can be obtained as follow:
Q = MCΔT
Q = 20 x 1 x 80
Q = 1600 calories
Therefore, the heat absorbed by the water is 1600 calories
