Answer:
The volume occupies of neon gas is 335, 7 L
Explanation:
We use the formula PV=nRT. We convert the unit temperature Celsius into Kelvin: 0°C=273 K---> -28°C= -28+273= 245K. We calculate the number of mols in 322 grams of neon:
20,18 g---1 mol neon
322g---x= (322g x 1 mol neon)/ 20, 18g=15, 96 mol neon
PV=nRT ----> V= (nRT)/P
V= (15,96 mol x 0,082 l atm/K mol x 245 K)/ 0,955 atm= 335, 7 L
