Answer:
17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.
Explanation:
[tex]Molarity=\frac{\text{Moles of substance}}{\text{Volume of solution in L}}[/tex]
We have:
Molarity of the NaCl solution = 6.32 M
Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L
1 mL = 0.001 L
Let the moles of NaCl be n.
[tex]6.32 M=\frac{n}{2.719 L}[/tex]
[tex]n=6.32M\times 2.719 L=17.18 mol[/tex]
17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.
