Respuesta :

gianna0011
that’s picture right there should help u with your works
Ver imagen gianna0011
Cricetus

The factor would be "[tex]\frac{1}{1024}[/tex]".

According to the question,

  • [tex]51 \ minutes = 10 \frac{1}{2} \ lifes[/tex]

Copper's half life,

  • 5.10 minutes

Now,

The factor would the mass of a sample of copper-66  decrease in 51 minutes would be:

→ [tex]\frac{5.10}{51} = 10[/tex]

then,

→ [tex](\frac{1}{2})^{10} = \frac{1}{1024}[/tex]

Thus the answer above is right.

Learn more:

https://brainly.com/question/18248273