Answer:
0.125 L
Explanation:
Given data:
Initial volume = ?
Initial molarity of NaCl = 3.00 M
Final volume = 0.300 L
Final molarity = 1.25 M
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume
M₂ = Final molarity
V₂ = Final volume
Now we will put the values in formula:
3.00 M × V₁ = 1.25 M × 0.300 L
3.00 M × V₁ = 0.375 M.L
V₁ = 0.375 M.L/3.00 M
V₁ =0.125 L
0.125 L of 3.00M NaCl stock solution would be use to make 0.300 L of a 1.25M NaCl solution.
