Answer:
a ≠ 2
Step-by-step explanation:
Given
[tex]\frac{a^2}{-3a+6}[/tex]
The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that a cannot be, that is
- 3a + 6 = 0 ( subtract 6 from both sides )
- 3a = - 6 ( divide both sides by - 3 )
a = 2 ← excluded value
