The distance between two points is [tex]\sqrt{98}[/tex] or 9.9 units
Solution:
The distance between two points is given as:
[tex]d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
From given,
[tex](x_1, x_2) = (-5, 5)\\\\(x_2, y_2) = (2, -2)[/tex]
Substituting the values we get,
[tex]d = \sqrt{(2+5)^2+(-2-5)^2}\\\\d = \sqrt{7^2+(-7)^2}\\\\d = \sqrt{49+49}\\\\d = \sqrt{98}\\\\d = 9.899 \approx 9.9[/tex]
Thus the distance between two points is [tex]\sqrt{98}[/tex] or 9.9 units
