Answer:
62.92°
Explanation:
given,
initial mass of water, m₁ = 71.8 g
initial temperature, T₁ = 78.8°C
another mass of water, m₂ = 33.6 g
another temperature of water, T₂ = 29° C
Final temperature of mix = ?
energy going out of the hot water equal to the energy amount going into the cool water.
[tex]q_{lost} =q_{gain}[/tex]
[tex]m_1 c \Delta T = m_1 c \Delta T[/tex]
[tex]71.8 (78.8-x) = 33.6\times (x - 29)[/tex]
[tex] 105.4 x = 6632.24[/tex]
x = 62.92°
Hence, the final temperature of the mix is equal to 62.92°
