Answer:
W=2.60 J
Explanation:
Given that
m = 41 kg
d= 10.6 mm
Coefficient of friction = 0.6
Friction force ,Fr=μ m g
Fr= 0.6 x 41 x 10 N ( take g= 10 m/s²)
Fr= 246 N
We know that work done by a force given as
W = F . d
Now by putting the values
W= 246 x 10.6 x 10 ⁻³ J
W=2.60 J
Therefore the work done by movers in the horizontal direction will be 2.60 J.The mover does the work against the friction force.
