Answer:
f(2k)=0
Step-by-step explanation:
Let's suppose f(x) is such that (x-2k) is one of its factors. We can write it as
f(x)=(x-2k).g(x)
Where g(x) is any other function of x, and g(x) in non-divisible by (x-2k). If we replace x=2k into f, we get
f(2k)=(0).g(2k)=0
f(2k)=0
