Answer:
k = 2
Step-by-step explanation:
[tex]\text{Put the coordinates of the given point A(2, 3)}\\\text{to the equation of a line}\ kx-2y+k=0:\\\\A(2,\ 3)\to x=2,\ y=3\\\\(k)(2)-(2)(3)+k=0\\2k-6+k=0\qquad\text{add 6 to both sides}\\2k+k=6\\3k=6\qquad\text{divide both sides by 3}\\\boxed{k=2}[/tex]
