Respuesta :
Answer:
0.02x + 0.28y = 0.5 is the required answer.
Step-by-step explanation:
Given:
[tex]4x+56y=100[/tex]
To Find :
Expression when it is divided by 200.
Solution:
[tex]4x+56y=100[/tex]
After Dividing both the side by 200 we get
[tex]\frac{4x}{200}+ \frac{56y}{200}= \frac{100}{200}\\\frac{x}{50}+ \frac{14y}{50}= \frac{1}{2}\\\therefore 0.02x+0.28y=0.5[/tex]
Which is the required Expression after Dividing by 200.
∴ 0.02x + 0.28y = 0.5 is the required answer.
