3x² - x = 10
3x² - x - 10 = 0
Δ = b² - 4.a.c
Δ = -1² - 4 . 3 . -10
Δ = 1 - 4. 3 . -10
Δ = 121
There are 2 real roots.
x = (-b +- √Δ)/2a
x' = (--1 + √121)/2.3
x'' = (--1 - √121)/2.3
x' = 12 / 6
x'' = -10 / 6
x' = 2
x'' = -5/3
Answer:
3x^2 - x - 10 = 0
3x^2 - 6x + 5x - 10 = 0
3x(x - 2) + 5(x - 2) = 0
(3x + 5)(x - 2) = 0
x = -5/3 , 2
Step-by-step explanation:
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