Answer:
[tex]x>5[/tex]
Step-by-step explanation:
We are asked to find an integer x such that [tex]\frac{x^3}{5}>x^2[/tex].
First of all, we will multiply both sides of inequality by 5.
[tex]\frac{x^3}{5}>x^2[/tex]
[tex]\frac{x^3}{5}*5>5*x^2[/tex]
[tex]x^3>5x^2[/tex]
Divide both sides by [tex]x^2[/tex]:
[tex]\frac{x^3}{x^2}>\frac{5x^2}{x^2}[/tex]
[tex]x>5[/tex]
Therefore, the value of x is any number greater than 5.
