Answer:
[tex]g(n-7)=\frac{n^2-14n+44}{3n-21}[/tex]
Step-by-step explanation:
The given function is
[tex]g(x)=\frac{x^2-5}{3x}[/tex]
To find g(n-7), we substitute x=n-7 to obtain;
[tex]g(n-7)=\frac{(n-7)^2-5}{3(n-7)}[/tex]
Expand the parenthesis to obtain;
[tex]g(n-7)=\frac{n^2-14n+49-5}{3n-21}[/tex]
Simplify:
[tex]g(n-7)=\frac{n^2-14n+44}{3n-21}[/tex]
